doing an integral whenever i remember until i forget (day 3)

[PerfectTierSquidward]

hey guys welcome back to another episode of squidwards unretirement
today's integral is this guy

we begin with a simple sub of letting x be -u, which gives us this

multiply by e^x to get something interesting..

note that our new I has the same denominator with a very similar numerator.... let's add up our two different expressions by the linearity of the integral operator

look at that, the annoying denominator vanishes.
so we get...

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